-14x^2+29x-3=0

Solution for -14x^2+29x-3=0 equation:

-14x^2+29x-3=0

a = -14; b = 29; c = -3;
Δ = b2-4ac
Δ = 292-4·(-14)·(-3)
Δ = 673
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{673}}{2*-14}=\frac{-29-\sqrt{673}}{-28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{673}}{2*-14}=\frac{-29+\sqrt{673}}{-28}
$